Asked by Gray
A bird drops a stick to the ground from a height of 68ft. The function h=-16t^2+68 gives the stick's approximate height h above the ground, in feet after t seconds. At about what time does the stick hit the ground
Answers
Answered by
Bosnian
The stick will hit the ground when h = 0
- 16 t² + 68 =0
Multiply both sides by - 1
16 t² - 68 =0
Add 68 to both sides
16 t² = 68
t² = 68 / 16 = 4 ∙ 17 / 4 ∙ 4 = 17 / 4
t = ± √17 / √4 = ± √17 / 2
Time can't be be negative so:
t = √17 / 2
t = 2.0615528128 sec
- 16 t² + 68 =0
Multiply both sides by - 1
16 t² - 68 =0
Add 68 to both sides
16 t² = 68
t² = 68 / 16 = 4 ∙ 17 / 4 ∙ 4 = 17 / 4
t = ± √17 / √4 = ± √17 / 2
Time can't be be negative so:
t = √17 / 2
t = 2.0615528128 sec
Answered by
Gray
Thank you so much:)
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