90 degrees is a quarter of 360
so
perimeter of sector = (1/4) ( 2 pi R)
Calculate the perimeter of a sector of a circle whose radius is 6cm and the angle substended at the centre is 90degree
3 answers
88/7cm
Using the formula, we have:
perimeter of sector = (1/4) (2 π R)
Substituting R = 6 cm and π = 22/7, we get:
perimeter of sector = (1/4) (2 × 22/7 × 6)
perimeter of sector = (1/4) (44/7 × 3)
perimeter of sector = (1/4) (132/7)
perimeter of sector = 33/7 cm
Therefore, the perimeter of the sector is 33/7 cm or approximately 4.71 cm (rounded to two decimal places).
perimeter of sector = (1/4) (2 π R)
Substituting R = 6 cm and π = 22/7, we get:
perimeter of sector = (1/4) (2 × 22/7 × 6)
perimeter of sector = (1/4) (44/7 × 3)
perimeter of sector = (1/4) (132/7)
perimeter of sector = 33/7 cm
Therefore, the perimeter of the sector is 33/7 cm or approximately 4.71 cm (rounded to two decimal places).