what mass of(Pb into No3) would be required to 9g of Pb CL2 of the addition of excess sodium chloride solution
2 answers
what mass of ( Pb into NO3 ) would be required to 9g of Pb CL2 of the addition of excess sodium chloride solution
Let me see if I can rewrite the question to make better sense.
What mass of Pb(NO3)2 would be required to produce 9g of PbCl2 upon the addition of excess sodium chloride solution? I think that is what you're asking.
Pb(NO3)2 + 2NaCl ==> PbCl2 + 2NaNO3
I've used Pb = 207 and Cl = 2*35.5 = 278
moles PbCl2 = grams/molar mass = 9/278 = approximately 0.0327
0.0327 moles PbCl2 will required 0.0327 moles of Pb(NO3)2. How many grams is this? That's 0.0327 mols Pb(NO3)2 x molar mass Pb(NO3)2 = ?
What mass of Pb(NO3)2 would be required to produce 9g of PbCl2 upon the addition of excess sodium chloride solution? I think that is what you're asking.
Pb(NO3)2 + 2NaCl ==> PbCl2 + 2NaNO3
I've used Pb = 207 and Cl = 2*35.5 = 278
moles PbCl2 = grams/molar mass = 9/278 = approximately 0.0327
0.0327 moles PbCl2 will required 0.0327 moles of Pb(NO3)2. How many grams is this? That's 0.0327 mols Pb(NO3)2 x molar mass Pb(NO3)2 = ?