Asked by Gabriel
An effort of 250N raises aload of 900N through 5M when using asimple machine.The effort moved through 25M.calculate the work input ofthe machine
Answers
Answered by
Anonymous
250 N * 25 m = 6250 Joules work input
by the way
900 N *5 m = 4500 Joules work output
efficiency = 100 * output/input = 100 { 4500/6250} = 72% efficiency
by the way
900 N *5 m = 4500 Joules work output
efficiency = 100 * output/input = 100 { 4500/6250} = 72% efficiency
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