Asked by Anonymous
                If a municipal reservoir containing 489.0 acre-feet of water is drained at a rate of 2000.0 gallons every hour, how many days will it take to completely empty the reservoir
            
            
        Answers
                    Answered by
            DrBob222   
            
    I asked Google to convert 489 acre-feet to gallons and Google came up with 1.593e+8 gallons. So 1.593e8 gallons x 1 hr/2000 gallon x (1 day/24 hr) = ? days. 
BTW this look much more like a math problem than a chemistry problem. oobleck should check this out.
    
BTW this look much more like a math problem than a chemistry problem. oobleck should check this out.
                    Answered by
            oobleck
            
    1 acre-foot is 43560 ft^3
so,
489*43560 ft^3 * 7.48gal/ft^3 * 1hr/20000gal * 1day/24hr = 331.938 days
    
so,
489*43560 ft^3 * 7.48gal/ft^3 * 1hr/20000gal * 1day/24hr = 331.938 days
                    Answered by
            DrBob222   
            
    1.593e8 gallons x 1 hr/2000 gallon x (1 day/24 hr) = 3319 days. 
489*43560 ft^3 * 7.48gal/ft^3 * 1hr/20000gal * 1day/24hr = 331.938 days
oobleck made a typo and entered 20,000 gallons/hr and not 2000 gallons/hr so his corrected answer is 3319 days also.
    
489*43560 ft^3 * 7.48gal/ft^3 * 1hr/20000gal * 1day/24hr = 331.938 days
oobleck made a typo and entered 20,000 gallons/hr and not 2000 gallons/hr so his corrected answer is 3319 days also.
                    Answered by
            oobleck
            
    dang - I missed that pesky decimal point.
Muchas gracias, DrBobxxx
    
Muchas gracias, DrBobxxx
                    Answered by
            DrBob222   
            
    There is nothing like a good ol' pesky decimal point. 
    
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