Question

Triangle ABC has measurements of AB=3.5cm and AC= 3.2cm. Given that the area of ABC = 3.36cm^2, (a)find angle A and (b) the length of the perpendicular from B to AC.
the area is 1/2 bc sinA, so
1/2 (3.5)(3.2) sinA = 3.36

If h is the length of the ⊥ from B to AC, then since area = 1/2 bh and b = AC,
1/2 (3.5) h = 3.36

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