Question
Aaron has a total of one hundred eighteen coins. If he had 5 times the number of Pennie’s and one-fourth the number of nickels, he would have $2.93 less. How much money does he have?
Answers
Anonymous
p + n = 118 (1)
5(p) + 1/4(5n) = 293 (2)
5p + 5/4n = 293 (2)
From (1) :
n = 118 - p -> substitute to (2)
5p + 5/4 (118 - p) = 293
5p + 295/2 - 5/4p = 293
15/4p = 293 - 295/2
15/4p = 291/2
p = (291 (4))/15 (2)
p = 38.8
p ≈ 39 -> number of pennies
n = 118 - p = 118 - 38 * 8
n = 79.2 ≈ 79 -> number of nickels
5(p) + 1/4(5n) = 293 (2)
5p + 5/4n = 293 (2)
From (1) :
n = 118 - p -> substitute to (2)
5p + 5/4 (118 - p) = 293
5p + 295/2 - 5/4p = 293
15/4p = 293 - 295/2
15/4p = 291/2
p = (291 (4))/15 (2)
p = 38.8
p ≈ 39 -> number of pennies
n = 118 - p = 118 - 38 * 8
n = 79.2 ≈ 79 -> number of nickels