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Given that sin 2x=cos (3x-10°) , find tan x

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since sin(x) = cos(90-x), we have
cos(90-2x) = cos(3x-10)
90-2x = 3x-10
x = 20
tan20° = 0.364
the period is 360/5 = 72°
so x = 20° + 72n°
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