Asked by Mark
Calculate the change in temperature when 6.00 L at 20.0 °C is compressed to 4.00 L.
Answers
Answered by
DrBob222
Is this a gas?
(V1/T2) = (V2/T2)
V1 = 4.00 L
V2 = 6.00 L
T1 = 20 C = 273 + 20 = 293 K
T2 = ? Solve for T2 in kelvin
The problem asks for CHANGE in T; therefore, T2 - T1 = delta T.
(V1/T2) = (V2/T2)
V1 = 4.00 L
V2 = 6.00 L
T1 = 20 C = 273 + 20 = 293 K
T2 = ? Solve for T2 in kelvin
The problem asks for CHANGE in T; therefore, T2 - T1 = delta T.