Part A) Since Anton wants the image width to be 100 inches, what is the distance the lens needs to be from the house if the Throw Ratio is 2.3?

Question

Part B) On the side of Anton’s house, he could have an image width of 130 inches. If the projector lens was going to be 280 inches from the screen then what is the throw ratio needed?

Part C) Movies are typically filmed at a ratio of 2.35 : 1 even though most televisions have a ratio of 16 : 9. This means that for every 2.35 inches wide the image is 1 inch tall.

If Anton wanted a screen with a ratio of 2.35 : 1 and the projector had a Throw Ratio of 1.6 then what is the area of the viewing space if the projector’s lens was 120 inches away from the screen?
*Area = length times width

Please help I need to get this done ASAP