Question

use the chain rule, in leibniz notation, to find dy/dx at the indicated value of x.

y = u^3 - 2(u - 3)^4, u = x + x^1/3, x = 1

Answer 1

dy/dx = dy/du du/dx
= (3u^2 - 8(u-3)^3 ) (1 + 1/3 x^-2/3)
u(1) = 2 so at x=2,
dy/dx = (3*2^2 - 8(1)^3) (1 + 1/3) = 16/3

Answer 2

sorry, how exactly did you get that answer? i'm confused with the steps i need to take