Asked by camille
y=sec^3(2x)+3sec2x
Answers
Answered by
oobleck
what about it? I guess since this is for calculus, you want the derivative or the integral
y' = 6sec2x tan2x (sec^2(2x) + 1)
∫y dx is complicated enough that I doubt that's what you are after.
y' = 6sec2x tan2x (sec^2(2x) + 1)
∫y dx is complicated enough that I doubt that's what you are after.
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