Asked by EMMANUEL
CACULATE THE PERCENTAGE BY MASS OFALL THE COMPONET ELEMENT IN SODIUM HYDROXODE NA=23,=O=16 H=1
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Answered by
Anonymous
Na O H = 23 + 16 + 1 = 40
Na: 100 *23/40 = 57.5 %
so you do the O and the H
Na: 100 *23/40 = 57.5 %
so you do the O and the H
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