Asked by Anonymous
Bryan had some stickers. He gave 1/5 of his stickers to John and bought 4 new stickers. After that, he gave 1/3 of his remaining stickers to his brother and bought another 7 new stickers. In the end, Bryan had 55 stickers.
(a) How many stickers did Bryan give to his brother?
(b) How many stickers did Bryan have at first?
(a) How many stickers did Bryan give to his brother?
(b) How many stickers did Bryan have at first?
Answers
Answered by
Anonymous
Let initial no. of stickers = N
Given to John = N/5
Remaining = N - N/5 = 4N/5
Bought 4 New
Now, no. of tickets = 4N/5 + 4
Given to brother = 1/3 of (4N/5 + 4)
= 4N/15 + 4/3
Remaining = (4N/5 + 4) - (4N/15 + 4/3)
= 4N/5 - 4N/15 + 4 - 4/3
= 8N/15 + 8/3
Bought 7 New
no. of stickers = 8N/15 + 8/3 + 7
= 8N/15 + 29/3
Now Bryan has 55
8N/15 + 29/3 = 55
8N/15 = 55 - 29/3 = 136/3
N = (136 * 15)/3 * 8 = 85
4N/15 + 4/3 = (4 * 85)/15 + 4/3
= (4 * 17)/3 + 4/3 = (68 + 4)/3
= 72/3 = 24
Given to John = N/5
Remaining = N - N/5 = 4N/5
Bought 4 New
Now, no. of tickets = 4N/5 + 4
Given to brother = 1/3 of (4N/5 + 4)
= 4N/15 + 4/3
Remaining = (4N/5 + 4) - (4N/15 + 4/3)
= 4N/5 - 4N/15 + 4 - 4/3
= 8N/15 + 8/3
Bought 7 New
no. of stickers = 8N/15 + 8/3 + 7
= 8N/15 + 29/3
Now Bryan has 55
8N/15 + 29/3 = 55
8N/15 = 55 - 29/3 = 136/3
N = (136 * 15)/3 * 8 = 85
4N/15 + 4/3 = (4 * 85)/15 + 4/3
= (4 * 17)/3 + 4/3 = (68 + 4)/3
= 72/3 = 24