Asked by Paul
The foot F of a vertical tower FT is 7m from a point on a bearing of N58E.A man walks 12m on a bearing of 288 and sees, the top T of the tower at an angle of elevation of 45.Find the height of the tower and the distance of the man from its foot.
Answers
Answered by
oobleck
assuming the man walked from "the point", then if the man ends up at point M, we have
MF^2 = 12^2 + 7^2 - 2*7*12*cos(130°)
MF = 17.35
That means the height of the tower is also 17.35 m
MF^2 = 12^2 + 7^2 - 2*7*12*cos(130°)
MF = 17.35
That means the height of the tower is also 17.35 m
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