Asked by Serena
The head of a pin has a diameter of 1 X 10^-4 meter. A bacterium has a diameter of 5 X 10-7 meter. How many bacteria that size would fit across the diameter of the pinhead?
Answers
Answered by
Anonymous
in line across?
10 * 10^-5 / (5 * 10^-7) = 2 * 10^(-5+7) = 2 *10^2 = 200
10 * 10^-5 / (5 * 10^-7) = 2 * 10^(-5+7) = 2 *10^2 = 200
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