Asked by <3
A car park charges £1.20 to each car entering.
The payment station only accepts £1 coins and 20p coins.
Here are the coins collected from the payment station on a particular day.
Number of £1 coins: 176
Number of 20p coins: 320
Assuming each driver paid the exact amount due on that day, work out the percentage of drivers that paid with six 20p coins
tyy :)
The payment station only accepts £1 coins and 20p coins.
Here are the coins collected from the payment station on a particular day.
Number of £1 coins: 176
Number of 20p coins: 320
Assuming each driver paid the exact amount due on that day, work out the percentage of drivers that paid with six 20p coins
tyy :)
Answers
Answered by
<3
if it helps, i know that the answer is 12%. i would be grateful for an explanation though! :)
Answered by
Bosnian
If has 176 £1 coins then 176 drivers paid £1 and 20 p coins.
The rest of the driver paid with 20 p coins.
So the number of 20 p coins is:
320 - 176 = 144
Since £1 and 20 p need 6 coins of 20 p, the number of drivers who paid only for 20 p coins is:
144 / 6 = 24
The total number of drivers is:
176 + 24 = 200
The percentage of drivers who paid only with coins id 20 p is:
24 / 200 • 100% =
0.12 • 100% = 12%
The rest of the driver paid with 20 p coins.
So the number of 20 p coins is:
320 - 176 = 144
Since £1 and 20 p need 6 coins of 20 p, the number of drivers who paid only for 20 p coins is:
144 / 6 = 24
The total number of drivers is:
176 + 24 = 200
The percentage of drivers who paid only with coins id 20 p is:
24 / 200 • 100% =
0.12 • 100% = 12%
Answered by
Bosnian
The rest of 20 p coins is:
320 - 176 = 144
320 - 176 = 144
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