Question
A hiker walks 250 meters at 40 degrees south of west and then goes 500 meters due north. What displacement vector will get the hiker back to where he started?
Answers
where was hiker at?
west dist 250 cos 40 = 192
north dist = 500 - 259 sin 40 = 333.5
so must go 333.5 south and 192 east
angle south of east = arc tan (333.5 / 192)
west dist 250 cos 40 = 192
north dist = 500 - 259 sin 40 = 333.5
so must go 333.5 south and 192 east
angle south of east = arc tan (333.5 / 192)
Related Questions
A hiker follows a route that consists of three displacement vectors A, B, and C. Vector A is along...
a man walks 10 meters in a direction of 20 degrees North of East, then 20 meters in a direction due...
On a 3 day hike a hiker walks 40 km due south the first day, 30 km at an angle of 40 degrees south o...
A hiker walks 10.0 km [n], 6.8km [w], 2.4km [s] and finally 1.2km [w] in 2.5hrs.
a) What is the hik...