Asked by Maria
A force vector f1 has a magnitude of 50 north it makes a 45 degree angle with a positive x axis. F2 has a magnitude of 70 north and points straight down. Determine the vector that results from adding f1 and f2
Answers
Answered by
oobleck
are "north" and "down" related to the x,y,z axes?
Answered by
Scott
I think?
Answered by
Maria
I’m not sure. I just started this course. I think so. Do you know how to solve it or get it started?
Answered by
oobleck
ok - I think "north" is a typo, maybe for Newtons
That means that
F1 = 50 cos45° i + 50sin45° j = 35.35i + 35.35j
F2 = -70j
So F1+F2 = 35.35i - 34.65j
Now, that's almost the same as 35.35i - 35.35j
which would be 50N at an angle of -45° to the x-axis.
To be more exact, it would be
50/√2 i + (50/√2 - 70)j or
49.50N at an angle of θ where
tanθ = (50/√2 - 70) / (50/√2) = -0.9799
θ = -44.418°
That means that
F1 = 50 cos45° i + 50sin45° j = 35.35i + 35.35j
F2 = -70j
So F1+F2 = 35.35i - 34.65j
Now, that's almost the same as 35.35i - 35.35j
which would be 50N at an angle of -45° to the x-axis.
To be more exact, it would be
50/√2 i + (50/√2 - 70)j or
49.50N at an angle of θ where
tanθ = (50/√2 - 70) / (50/√2) = -0.9799
θ = -44.418°
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.