Asked by Ayo

4x+y=7 5x+3y=7
Answered by R_scott
multiply 1st eqn. by 3 ... 12x + 3y = 21

subtract 2nd eqn. (to eliminate y) ... 12x + 3y - 5x - 3y = 21 - 7
... 7x = 14

solve for x , then substitute back to find y
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