A copper rod is 2m long at a certain temperature. what will be its length for the temperature change of 100k if it linear expansivity l= 0.000017k

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A copper rod is 2m at a certain temperature. What will be it's length for a temperature change of lookelvin if it's linear expansivity
Yes
delta L / L = 0.000017 * 100 = 0.0017
delta L = 2 * 0.0017 = 0.0034 meters = 0.34 centimeters
Calculate the increase in length of a 2m copper that is hated from 9°c to150°c
We can use the formula below to calculate the increase in length of the copper rod:

ΔL = L * α * ΔT

Where:

ΔL = change in length
L = initial length of the copper rod (2m)
α = coefficient of linear expansion of copper (0.000017 / °C)
ΔT = change in temperature (150°C - 9°C = 141°C)

So,

ΔL = 2 * 0.000017 * 141
= 0.004794 meters
= 4.794 millimeters

Therefore, the increase in length of the copper rod is approximately 4.794 millimeters.
Calculate the increas in length of a 2m copper and rod that is heated from 0°c to 150°
We can use the formula below to calculate the increase in length of the copper rod:

ΔL = L * α * ΔT

Where:

ΔL = change in length
L = initial length of the copper rod (2m)
α = coefficient of linear expansion of copper (0.000017 / °C)
ΔT = change in temperature (150°C - 0°C = 150°C)

So,

ΔL = 2 * 0.000017 * 150
= 0.0051 meters
= 5.1 millimeters

Therefore, the increase in length of the copper rod is approximately 5.1 millimeters.