Asked by Anonymous
A copper rod is 2m long at a certain temperature. what will be its length for the temperature change of 100k if it linear expansivity l= 0.000017k
Answers
Answered by
Anonymous
I need help for the question
Answered by
Tarnum Tyover
A copper rod is 2m at a certain temperature. What will be it's length for a temperature change of lookelvin if it's linear expansivity
Answered by
Tarnum Tyover
Yes
Answered by
Anonymous
delta L / L = 0.000017 * 100 = 0.0017
delta L = 2 * 0.0017 = 0.0034 meters = 0.34 centimeters
delta L = 2 * 0.0017 = 0.0034 meters = 0.34 centimeters
Answer
Calculate the increase in length of a 2m copper that is hated from 9°c to150°c
Answer
Calculate the increas in length of a 2m copper and rod that is heated from 0°c to 150°
Answered by
Bot
We can use the formula below to calculate the increase in length of the copper rod:
ΔL = L * α * ΔT
Where:
ΔL = change in length
L = initial length of the copper rod (2m)
α = coefficient of linear expansion of copper (0.000017 / °C)
ΔT = change in temperature (150°C - 9°C = 141°C)
So,
ΔL = 2 * 0.000017 * 141
= 0.004794 meters
= 4.794 millimeters
Therefore, the increase in length of the copper rod is approximately 4.794 millimeters.
ΔL = L * α * ΔT
Where:
ΔL = change in length
L = initial length of the copper rod (2m)
α = coefficient of linear expansion of copper (0.000017 / °C)
ΔT = change in temperature (150°C - 9°C = 141°C)
So,
ΔL = 2 * 0.000017 * 141
= 0.004794 meters
= 4.794 millimeters
Therefore, the increase in length of the copper rod is approximately 4.794 millimeters.
Answered by
Bot
We can use the formula below to calculate the increase in length of the copper rod:
ΔL = L * α * ΔT
Where:
ΔL = change in length
L = initial length of the copper rod (2m)
α = coefficient of linear expansion of copper (0.000017 / °C)
ΔT = change in temperature (150°C - 0°C = 150°C)
So,
ΔL = 2 * 0.000017 * 150
= 0.0051 meters
= 5.1 millimeters
Therefore, the increase in length of the copper rod is approximately 5.1 millimeters.
ΔL = L * α * ΔT
Where:
ΔL = change in length
L = initial length of the copper rod (2m)
α = coefficient of linear expansion of copper (0.000017 / °C)
ΔT = change in temperature (150°C - 0°C = 150°C)
So,
ΔL = 2 * 0.000017 * 150
= 0.0051 meters
= 5.1 millimeters
Therefore, the increase in length of the copper rod is approximately 5.1 millimeters.
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