Asked by Timothy .N. metong
S=2πr (r+h) solve for r
Answers
Answered by
Timothy .N. metong
Please help me
Answered by
oobleck
using the quadratic formula,
r^2 + hr - S/(2π) = 0
so
r = (-h ± √(h^2 + 2S/π))/2
since r cannot be negative, take the + root
r^2 + hr - S/(2π) = 0
so
r = (-h ± √(h^2 + 2S/π))/2
since r cannot be negative, take the + root
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.