S=2πr (r+h) solve for r
2 answers
Please help me
using the quadratic formula,
r^2 + hr - S/(2π) = 0
so
r = (-h ± √(h^2 + 2S/π))/2
since r cannot be negative, take the + root
r^2 + hr - S/(2π) = 0
so
r = (-h ± √(h^2 + 2S/π))/2
since r cannot be negative, take the + root
1 answer