How do I figure these 2 out.
Find standard form a +bi
(4 square root -9) ( -3 square root -5)
x^2 -3x+4 evaluated for x=1+i
3 answers
For the second one i got 1+3i is this correct
4 (-9)^.5 * -3 (-5)^.5
-12 (45)^.5
-12 (3*3*5)^.5
-36 sqrt 5
(1+i)^2 -3(1+i) + 4
=
1 + 2 i - 1 - 3 - 3 i + 4
=
(1 -i)
-12 (45)^.5
-12 (3*3*5)^.5
-36 sqrt 5
(1+i)^2 -3(1+i) + 4
=
1 + 2 i - 1 - 3 - 3 i + 4
=
(1 -i)
Doesnt i^2 equal -1