Asked by Austin
An excess of Ca(s) is added to 180g of distilled water at STP. What volume of H2 gas can be produced?
a) 448 L
b) 224 L
c) 112 L
d) 22.4 L
a) 448 L
b) 224 L
c) 112 L
d) 22.4 L
Answers
Answered by
DrBob222
...................Ca + 2H2O ==> Ca(OH)2 + H2
moles H2O = grams/molr mass = 180/18 = 10
Convert mols H2O to mols H2 this way:
1moles H2 gas = 0 mols H2O x (1 mol H2/2 mols H2O) = 10 x 1/2 = 5
You know 1 mol of gas occupies 22.4 L @ STP; therefore, volume H2 = 5 moles H2 x (22.4 L/mol) = ?
moles H2O = grams/molr mass = 180/18 = 10
Convert mols H2O to mols H2 this way:
1moles H2 gas = 0 mols H2O x (1 mol H2/2 mols H2O) = 10 x 1/2 = 5
You know 1 mol of gas occupies 22.4 L @ STP; therefore, volume H2 = 5 moles H2 x (22.4 L/mol) = ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.