Asked by Labake

A student walks 50m on a bearing 025 degree and then 200m die east. How far is she from her starting point
Answered by AJ L
Use the Law of Cosines:

c = sqrt[a^2 + b^2 - 2ab*cos(θ)]
c = sqrt[50^2 + 200^2 - 2(50)(200)cos(115°)]
c ≈ 225.726

Therefore, the student is 225.726 meters from her starting point
Answered by marvelous
a student walks 50m on a bearing 025°and then 200m due east. how far is she from her starting point
Answered by Daniel
a²=200²+50²-2*200*50*Cos 65
a=226m
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