Asked by BBen
A solution containing nitric acid (HNO3) is to be used in the neutralization titration of a sodium hydroxide (NaOH) solution.
a. If the pH of the nitric acid solution is 2.30, what is the normality of the nitric acid?
b. If 27.00 ml of the nitric acid solution are required to neutralize 45.00 ml of the NaOH solution, what is the normality of the NaOH solution?
c. What was the pH of the NaOH solution before neutralization?
a. If the pH of the nitric acid solution is 2.30, what is the normality of the nitric acid?
b. If 27.00 ml of the nitric acid solution are required to neutralize 45.00 ml of the NaOH solution, what is the normality of the NaOH solution?
c. What was the pH of the NaOH solution before neutralization?
Answers
Answered by
DrBob222
a. pH = -log(HNO3)
2.30 -log(HNO3)
(HNO3) = ? in moles/L which is the same as equivalents/L = normality.
b. mLNaOH x N NaOH = mL HNO3 x N HNO3
You know mL NaOH, mL HNO3, and N HNO3. Solve for N NaOH
c. pOH = -log(NaOH)
Post your work if you get stuck.
Then pH + pOH = pKw = 14
You know pKw and you know pOH, solve for pH.
2.30 -log(HNO3)
(HNO3) = ? in moles/L which is the same as equivalents/L = normality.
b. mLNaOH x N NaOH = mL HNO3 x N HNO3
You know mL NaOH, mL HNO3, and N HNO3. Solve for N NaOH
c. pOH = -log(NaOH)
Post your work if you get stuck.
Then pH + pOH = pKw = 14
You know pKw and you know pOH, solve for pH.
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