Asked by Scott
The copper, zinc and nickel contents of the three different brasses
(A, B, C) are as follows:
A : (55 % Cu, 11 % Zn, 34 % Ni)
B : (48% Cu, 23 % Zn, 29 % Ni)
C : (51 % Cu, 10 % Zn, 39 % Ni)
-- How much of these alloys must be melted together to obtain about 14.0 kg of brass with 49.1 % copper, 19.4 % zinc and 31.5 % nickel?
[Cu, Zn, Ni] = ??
(A, B, C) are as follows:
A : (55 % Cu, 11 % Zn, 34 % Ni)
B : (48% Cu, 23 % Zn, 29 % Ni)
C : (51 % Cu, 10 % Zn, 39 % Ni)
-- How much of these alloys must be melted together to obtain about 14.0 kg of brass with 49.1 % copper, 19.4 % zinc and 31.5 % nickel?
[Cu, Zn, Ni] = ??
Answers
Answered by
oobleck
If the amounts of the three alloys are a,b,c then you have
0.55a + 0.48b + 0.51c = 0.491 * 14
0.11a + 0.23b + 0.10c = 0.194 * 14
0.34a + 0.29b + 0.39c = 0.215 * 14
Now just solve for a,b,c
0.55a + 0.48b + 0.51c = 0.491 * 14
0.11a + 0.23b + 0.10c = 0.194 * 14
0.34a + 0.29b + 0.39c = 0.215 * 14
Now just solve for a,b,c
Answered by
Scott
Can somebody give me the last answers so I check if I have them correct or not
Thanks in advance
Thanks in advance
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