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How many grams of Methane will be burned stoichiometrically using 23.6 grams of Oxygen?

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CH4 + O2 ==> CO2 + 2H2O
mols O2 = g/molar mass = 23.6/32 = 0.738
1 mol CH4 = 1 mol O2; therefore, 0.738 mols CH4
g CH4 = mols XH4 x molar mass CH4 = ?

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