Asked by Jack

Hi guys,
how to solve this: 1/3 log(base5) 3x + log(base5) 4=3
Please help math hero
Answered by Anonymous
Please clarify parentheses
1/3 log(base5) 3x + log(base5) 4=3
perhaps you mean:
1 / [3 log(base5) 3x + log(base5) 4 ] = 3
1 / [ log(base5) 27x^3 + log(base5) 4]=3
1 / log(base5) 108 x^3 =3
1 = 3 log(base5) 108 x^3
log(base5) 108^3 x^9 = 1
so 108^3 x ^9 = 5
about 0.25 ?
Answered by Jack
1/3log(base5) 3x + log(base5) 4=3
what I meant is: 1/3=one-third ,log5= log(base5)
Answered by oobleck
assuming base 5 throughout,
1/3 log3x + log4 = 3
log3x + 3log4 = 9
log(3x * 4^3) = 9
192x = 5^9
x = 5^9/192
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