Asked by Omar Villatoro
Solve each initial value problem.
a.) (12x5 + 2x2 −6)dx −2yx3dy = 0 with y(1) = 6
b.) x^3 dy/dx −x^2y = −xy^3 with y(1) = 1
a.) (12x5 + 2x2 −6)dx −2yx3dy = 0 with y(1) = 6
b.) x^3 dy/dx −x^2y = −xy^3 with y(1) = 1
Answers
Answered by
oobleck
(12x^5 + 2x^2 −6)dx −2yx^3dy = 0
2y dy = (12x^2 + 2/x - 6/x^3 dx
y^2 = 4x^3 + 2lnx + 3/x^2 + C
since y(1) = 6,
4+3 = C
y^2 = 4x^3 + 2lnx + 3/x^2 + 7
Now you try the other. Post your work if you get stuck
2y dy = (12x^2 + 2/x - 6/x^3 dx
y^2 = 4x^3 + 2lnx + 3/x^2 + C
since y(1) = 6,
4+3 = C
y^2 = 4x^3 + 2lnx + 3/x^2 + 7
Now you try the other. Post your work if you get stuck
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