Asked by MACK
A basketball team sells tickets that cost $10, $20, or, for VIP seats, $30. The team has sold 3203 tickets overall. It has sold 267 more $20 tickets than $10 tickets. The total sales are $62,610. How many tickets of each kind have been sold?
Answers
Answered by
oobleck
so, what have they told you?
If there are
x $10 seats
y $20 seats
z $30 seats, then
x+y+z = 3203
y = x+267
10x+20y+30z = 62610
Now just solve as usual for x,y,z
Post your work if you get stuck
If there are
x $10 seats
y $20 seats
z $30 seats, then
x+y+z = 3203
y = x+267
10x+20y+30z = 62610
Now just solve as usual for x,y,z
Post your work if you get stuck
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