Asked by lashawna calzada
the number of gallons in a fifty gallon fish tank after t number of minutes has passed.
y = -1.5 t + 48
1) Is the tank empty when the time is zero? If not, how many gallons are in the tank?
2) What does the number -1.5 mean in the context of the problem (what is it describing)?
3) After how many minutes would the tank be empty?
y = -1.5 t + 48
1) Is the tank empty when the time is zero? If not, how many gallons are in the tank?
2) What does the number -1.5 mean in the context of the problem (what is it describing)?
3) After how many minutes would the tank be empty?
Answers
Answered by
lashawna calzada
I would like for someone to please explain the formula that I would use to figure out this problem and others like it. like really explained please.
Answered by
Anonymous
1. when t = 0 there are 48 gallons in the tank :)
2, it loses 1.5 gallons per minute
3. 0 = -1.5 t + 48 so t = 48/1.5 when y = 0, a little over half an hour
2, it loses 1.5 gallons per minute
3. 0 = -1.5 t + 48 so t = 48/1.5 when y = 0, a little over half an hour
Answered by
Anonymous
you have the formula
y= number of gallons = 48 to start - 1.5 * minutes leaking
y= number of gallons = 48 to start - 1.5 * minutes leaking
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