Asked by Zak
The acceleration of an object is given by the following equation
a = 8t+7
where a is the acceleration in ms^-2 and t is time (secs)
when t = 0, Velocity is 4 ms^-1 and distance is 12 meters
Using Integral Calculus, find the equations for velocity, v, and distance, s, travelled
a = 8t+7
where a is the acceleration in ms^-2 and t is time (secs)
when t = 0, Velocity is 4 ms^-1 and distance is 12 meters
Using Integral Calculus, find the equations for velocity, v, and distance, s, travelled
Answers
Answered by
oobleck
a = 8t+7
v = 4t^2 + 7t + C
v(0) = 4, so C = 4
s = 4/3 t^3 + 7/2 t^2 + 4t + C
s(0) = 12, so
s = 4/3 t^3 + 7/2 t^2 + 4t + 12
v = 4t^2 + 7t + C
v(0) = 4, so C = 4
s = 4/3 t^3 + 7/2 t^2 + 4t + C
s(0) = 12, so
s = 4/3 t^3 + 7/2 t^2 + 4t + 12
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