Asked by mohamed
formula for initial velocity by projectile
Answers
Answered by
Anonymous
well, in general
S = takeoff velocity
e = elevation angle from horizontal
u = horizontal speed forever= S cos e
Vi = initial vertical speed = S sin e
v = vertical speed = Vi - g t
h = Hi + Vi t - (1/2) g t^2 where h is height and Hi is initial height
S = takeoff velocity
e = elevation angle from horizontal
u = horizontal speed forever= S cos e
Vi = initial vertical speed = S sin e
v = vertical speed = Vi - g t
h = Hi + Vi t - (1/2) g t^2 where h is height and Hi is initial height
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