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To find the effort required to lift a load of 200 Newtons, we need to consider two factors: the efficiency of the machine and its velocity ratio.

Efficiency is the ratio of output work to input work, expressed as a decimal or percentage. In this case, the efficiency is given as 80 percent, which can be converted to a decimal by dividing it by 100. So, the efficiency of the machine is 0.80.

Velocity ratio is the ratio of the distance moved by the effort to the distance moved by the load. In this case, the velocity ratio is given as 6. This means that for every unit of distance the effort moves, the load moves six times that distance.

To determine the effort required, we can use the formula:

Efficiency = (Output work / Input work) * 100

Since the efficiency is given as a percentage, we can rewrite the formula as:

Efficiency = (Output work / Input work) * 1

Now, let's plug in the given values:

0.80 = (Output work / Input work) * 1

Next, we can rearrange the formula to solve for the output work:

Output work = Efficiency * Input work

Since we have the velocity ratio, we can express the input work in terms of the load lifted:

Input work = Load * Distance moved by load

To find the distance moved by the load, we divide 1 by the velocity ratio:

Distance moved by load = 1 / Velocity ratio

Now, let's substitute the values:

Distance moved by load = 1 / 6 = 0.1667

Input work = 200 * 0.1667 = 33.34 joules

Finally, we can calculate the output work:

Output work = 0.80 * 33.34 = 26.67 joules

Therefore, the effort required to lift a load of 200 Newtons is approximately 26.67 joules.