Asked by David
The 4th and 7th terms of GP are 16 and 2 respectively.Find; a)the first term b)the common ratio c)the sum of the first 3 terms.
Answers
Answered by
oobleck
r^3 = 2/16 = 1/8
r = 1/2
a(1/2)^3 = 16, so a = 128
S3 = 128 (1 - 1/8)/(1 - 1/2) = 224
check: 128+64+32 = 224
r = 1/2
a(1/2)^3 = 16, so a = 128
S3 = 128 (1 - 1/8)/(1 - 1/2) = 224
check: 128+64+32 = 224
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