Asked by d'angleo k.
how many solutions the equations have:
x^2 - 2x + 1 = 0 & x^2 + 3 = 0
x^2 - 2x + 1 = 0 & x^2 + 3 = 0
Answers
Answered by
oobleck
check the discriminants.
or, note that
x^2-2x+1 = (x-1)^2
and since x^2 is always positive, x^2+3 can never be zero.
If you have a system, then they intersect where
-2x+1 = 3
x = -1
or, note that
x^2-2x+1 = (x-1)^2
and since x^2 is always positive, x^2+3 can never be zero.
If you have a system, then they intersect where
-2x+1 = 3
x = -1
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