Asked by Grant
Two planes flying opposite directions (north and south) pass each other 80 miles apart at the same altitude. The northbound plane is flying 200 mph (miles per hour) and the southbound plane is flying 150 mph. How far apart are the planes in 20 minutes? (Round your answer to one decimal place.)
This is what I did
Distance between these planes after 20 minutes or 1/3 hours.
In right angle triangle DEC,
DE = 80 miles
BE = (Speed × duration) = 200*1/3= 66.666667miles
Similarly, BC = 150*1/3=50 miles
By Pythagoras theorem,
DC² = EC² + DE²
= (EB + BC)² + DE²
= (66.67+ 50)² + (80)²
= 20011.8889
DC = √20011.8889 = 141.46 miles
What did I do wrong
This is what I did
Distance between these planes after 20 minutes or 1/3 hours.
In right angle triangle DEC,
DE = 80 miles
BE = (Speed × duration) = 200*1/3= 66.666667miles
Similarly, BC = 150*1/3=50 miles
By Pythagoras theorem,
DC² = EC² + DE²
= (EB + BC)² + DE²
= (66.67+ 50)² + (80)²
= 20011.8889
DC = √20011.8889 = 141.46 miles
What did I do wrong
Answers
Answered by
oobleck
Looks good to me.
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