Asked by Zein
A balloon is rising vertically 150 m from an observer. At exactly 1 min, the angle of elevation is 29 deg 28 min. How fast is the balloon rising at that instant?
Answers
Answered by
oobleck
Draw the diagram, and you will note that when the balloon is at height h,
h/150 = tanθ
That means that
1/150 dh/dt = sec^2θ dθ/dt
dh/dt =150 sec^2(29°28') dθ/dt
See what you can do with that.
h/150 = tanθ
That means that
1/150 dh/dt = sec^2θ dθ/dt
dh/dt =150 sec^2(29°28') dθ/dt
See what you can do with that.
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