Asked by meee
find the period, amplitude and phase angle of the function 2y=3 sin(1/2x-60)
Answers
Answered by
oobleck
recall that for the function
y = a sin(b(x-c))
you have
amplitude = a
period = 2π/b
phase shift = c (to the right)
So, your function is y = 3/2 sin(1/2 (x-120))
giving you
amplitude = 3/2
period = 2π/(1/2) = 4π
phase shift = 120
y = a sin(b(x-c))
you have
amplitude = a
period = 2π/b
phase shift = c (to the right)
So, your function is y = 3/2 sin(1/2 (x-120))
giving you
amplitude = 3/2
period = 2π/(1/2) = 4π
phase shift = 120