Asked by meee
                find the period, amplitude and phase angle of the function 2y=3 sin(1/2x-60)
            
            
        Answers
                    Answered by
            oobleck
            
    recall that for the function
y = a sin(b(x-c))
you have
amplitude = a
period = 2π/b
phase shift = c (to the right)
So, your function is y = 3/2 sin(1/2 (x-120))
giving you
amplitude = 3/2
period = 2π/(1/2) = 4π
phase shift = 120
    
y = a sin(b(x-c))
you have
amplitude = a
period = 2π/b
phase shift = c (to the right)
So, your function is y = 3/2 sin(1/2 (x-120))
giving you
amplitude = 3/2
period = 2π/(1/2) = 4π
phase shift = 120
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