Question
An ice skating competition features 8 skaters. How many different ways can the skaters finish the competition? How many different ways can 3 of the skaters finish first, second and third?
Answers
oobleck
8P8 = 8! = 40320
8P3 = 8*7*6 = 336
8P3 = 8*7*6 = 336
Soumik
8P8 = 8! = 40320
8P3 = 8*7*6 = 336
8P3 = 8*7*6 = 336