Asked by Muskan

An ice skating competition features 8 skaters. How many different ways can the skaters finish the competition? How many different ways can 3 of the skaters finish first, second and third?
Answered by oobleck
8P8 = 8! = 40320
8P3 = 8*7*6 = 336
Answered by Soumik
8P8 = 8! = 40320
8P3 = 8*7*6 = 336
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