distance = speed * time
So, if B traveled for time t hours, then
32(t+1) + (2*32)t = 512
Now just solve for t.
Town Y and Town Z were 512 km apart. Car A left Town Y for Town Z at a speed of 32km/h. An hour later car B left Town Z for Town Y at twice of car A ‘s speed. How long would it take for the two cars to pass each other after car b left town Z?
2 answers
when b leaves the distance between cars is d = 512 - 1 Sa
speed = Sa + Sb = Sa + 2Sa = 3 Sa
so
3 Sa t = 512 - 1 Sa
3 * 32 * t = 512-32 = 480
t = 480/96 = 5 hr
speed = Sa + Sb = Sa + 2Sa = 3 Sa
so
3 Sa t = 512 - 1 Sa
3 * 32 * t = 512-32 = 480
t = 480/96 = 5 hr