Asked by Anonymous
Find the angle from the line 2x+y-8=0 to the line x+3y+4=0
Answers
Answered by
oobleck
the slope of 2x+y-8=0 is -2
the slope of x+3y+4=0 is -1/3
arctan(-1/3) - arctan(-2) = 45°
the slope of x+3y+4=0 is -1/3
arctan(-1/3) - arctan(-2) = 45°
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