Asked by Anonymous
.a race car moving at a constant speed of 35m/s a security car was moving at 5m/s as a race car passes by it and accelerating at at a constant rate of 5m/s^2. what was the speed of the security car when it took over race car.
Answers
Answered by
oobleck
How long did it take to catch up? When the distances were the same:
35t = 5t + 5/2 t^2
so it took t=12 seconds. At that time, the car's speed was
v = 5+5*12 = 65 m/s
35t = 5t + 5/2 t^2
so it took t=12 seconds. At that time, the car's speed was
v = 5+5*12 = 65 m/s
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