Asked by Anjoy Aru
                 Find the volumes of the solids obtained by rotating the region bounded in the first quadrant by y=x^3 and x=1 , x-axis rotating about x-axis and y-axis.
            
            
        Answers
                    Answered by
            oobleck
            
    The curves intersect at (0,0) and (1,1), so
about the x-axis
using discs of thickness dx
v = ∫[0,1] πr^2 dx
where r = y = x^3
v = ∫[0,1] πx^6 dx
using shells of thickness dy
v = ∫[0,1] 2πrh dy
where r=1 and h=1-x
v = ∫[0,1] 2πy(1 - ∛y) dy
---------------------------------------------------
about the x-axis
using discs (washers) of thickness dy
v = ∫[0,1] π(R^2-r^2) dy
where R=1 and r=x=∛y
v = ∫[0,1] π(1-y^(2/3)) dy
using shells of thickness dx
v = ∫[0,1] 2πrh dx
where r=x and h=y
v = ∫[0,1] 2πx*x^3 dx
    
about the x-axis
using discs of thickness dx
v = ∫[0,1] πr^2 dx
where r = y = x^3
v = ∫[0,1] πx^6 dx
using shells of thickness dy
v = ∫[0,1] 2πrh dy
where r=1 and h=1-x
v = ∫[0,1] 2πy(1 - ∛y) dy
---------------------------------------------------
about the x-axis
using discs (washers) of thickness dy
v = ∫[0,1] π(R^2-r^2) dy
where R=1 and r=x=∛y
v = ∫[0,1] π(1-y^(2/3)) dy
using shells of thickness dx
v = ∫[0,1] 2πrh dx
where r=x and h=y
v = ∫[0,1] 2πx*x^3 dx
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