Asked by Anonymous


if you have a supply of 0.50M Ca(NO3)2 solution in your laboratory. How many milliliters of this solution do you have to evaporate to get 32.8g of solid Ca(NO3)2

Answers

Answered by oobleck
how many moles of Ca(NO3)2 in 32.8g? If it is x, then since 0.50M solution has 0.5 moles per liter, you will need 2x liters of solution.
or, 2000x mL
Answered by DrBob222
Another way but not any better.
molar mass Ca(NO3)2 = 40 + (14 + 48)*2 = 164 so 0.5M = 164/2 or 82 g/L.
82 g/L x ?L = 32.8
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