Asked by Berkley

A hockey puck has a coefficient of kinetic friction of μ = .10. If the puck feels a normal force (FN) of 5 N, what is the frictional force that acts on the puck?
Answered by Anonymous
0.10 * 5 = 0.5 Newtons
assuming that the force is normal to the ice (gravity not a stick or something)
Answered by kwazyy
1 * 5 = 5N
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