Question

Robins eat 12 worms in the morning on an average sunny day. On rainy days, robins average 4 fewer worms per morning. Last week, there were 3 sunny days and 4 rainy days. How many worms did a robin eat that week?

Answer 1

We shall split this into two parts, one is solving the number of worms a robin eats on a sunny day and one is is solving the number of worms a robin eats on a rainy day.

Part 1 - Sunny Day
12 x 3 = 36

Part 2 - Rainy Day
(12 - 4) x 4
= 8 x 4
= 32

Then, we add 36 + 32 = 68 worms.

Hope this helps!

Answer 2

(3 x 12) + (4 x 8) = 68 worms

Answer 3

That's correct! Another way to approach the problem is by using the distributive property of multiplication:

12 worms/day x (3 sunny days + 4 rainy days) = 12 x 7 = 84 worms

Then, we subtract the 4 fewer worms on rainy days:

84 - 4 x 4 = 68 worms

So, the robin ate 68 worms that week.