Asked by tom
(2y+1)/(y^2-y-6)
ruling out value for y.
which numbers can not be used in place of (y).
ruling out value for y.
which numbers can not be used in place of (y).
Answers
Answered by
Reiny
we cannot divide by zero
so the the problem arises when
y^2 - y - 6 = 0
(y-3)(y+2) = 0
y = 3 or y = -2
so y CANNOT be 3 or -2
so the the problem arises when
y^2 - y - 6 = 0
(y-3)(y+2) = 0
y = 3 or y = -2
so y CANNOT be 3 or -2
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