Asked by Fatima
A beam of ions passes undeflected through two parallel horizontal plates 1.5cm apart having a p.d of 3000v when a perpendicular magnetic field of 10-2T is applied and in the magnetic field alone beam is bent into a curve of radius 2m. Calculate the charge mass ratio of the ions
Answers
Answered by
Anonymous
E = 3000 / 0.015 vols/meter
F of E field = Q E
F of Bfield = Q v B
if the forces balance then
Q E = Q v B
E = v B
3000 / 0.015 vols/m = v * 10^-2 Tesla
v = 2 * 10^7 meters/s (about 1/10 speed of light)
Then
m v^2/R = centripetal force = Q v B
so
Q/m = v / RB = 2*10^7 / 2*10^-2 = 10^9
F of E field = Q E
F of Bfield = Q v B
if the forces balance then
Q E = Q v B
E = v B
3000 / 0.015 vols/m = v * 10^-2 Tesla
v = 2 * 10^7 meters/s (about 1/10 speed of light)
Then
m v^2/R = centripetal force = Q v B
so
Q/m = v / RB = 2*10^7 / 2*10^-2 = 10^9
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.